What fraction of chlorine will be precipitate | vedclass

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(B) The coordination compound $[CrCl(NH_3)_5]Cl_2$ dissociates in water to release the ions present outside the coordination sphere.The formula can be

Vedclass · Accepted Answer

$2/3$

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(B) The coordination compound $[CrCl(NH_3)_5]Cl_2$ dissociates in water to release the ions present outside the coordination sphere.The formula can be written as $[CrCl(NH_3)_5]^{2+} + 2Cl^-$.When $AgNO_3$ is added,it reacts with the ionizable chloride ions: $2Cl^- + 2AgNO_3 \rightarrow 2AgCl(s) + 2NO_3^-$.Total chlorine atoms in the compound = $3$.Ionizable chlorine atoms = $2$.Therefore,the fraction of chlorine precipitated as $AgCl$ is $2/3$.

What fraction of chlorine will be precipitated as $AgCl$ by using $AgNO_3$ from $[CrCl(NH_3)_5]Cl_2$?

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